In one fortnight of a given month there was a rainfall of 10 cm in a river valley.if the area of the valley is 7280 km2 , show that the total rainfall was approx equivalent to the addition to the normal water of three rivers each 1072 long, 75 m wide , 3 m deep
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Area of the valley, A = 97280 km^2
Level in the rise of water in the valley, h = 10 cm = (10/100000) km = (1/10000) km
Thus, amount of rain fall = Ah = 97280 km^2 × (1/10000) km = 9.828 km^3
in 14 days 9.828km^3 in 1 day 0.702km^3
Volume of water in each river = length × breadth × height = 1072 km × 75 m × 3 m = 1072 km × (75/1000) km × (3/1000) km = 0.2412 km^3
Thus, the volume of water in three rivers = 3 × 0.2412 km^3 = 0.7236 km^3
and amt of rainfall= 0.702 km^3 which is approximately equal
This shows that the amount of rain fall is approximately equal to the amount of water in three rivers.
Level in the rise of water in the valley, h = 10 cm = (10/100000) km = (1/10000) km
Thus, amount of rain fall = Ah = 97280 km^2 × (1/10000) km = 9.828 km^3
in 14 days 9.828km^3 in 1 day 0.702km^3
Volume of water in each river = length × breadth × height = 1072 km × 75 m × 3 m = 1072 km × (75/1000) km × (3/1000) km = 0.2412 km^3
Thus, the volume of water in three rivers = 3 × 0.2412 km^3 = 0.7236 km^3
and amt of rainfall= 0.702 km^3 which is approximately equal
This shows that the amount of rain fall is approximately equal to the amount of water in three rivers.
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