Question

In a triangle ABC right angled at B, AB = 5 cm and AC = 10 cm. Determine ∠ BAC and ∠ BCA.

Answer 1

Answer:

Aɴsᴡᴇʀ~❤️

In ΔABC, <B = 90°

= AB = 5cm

= AC = 10cm

= Sin θ = 5/10 = 1/2

= <BCA = sin^{-1}sin

−1

(1/2) = 30°

= <BCA = 30°

= <BAC = 90° - <BCA (30°)

= <BAC = 90° - 30° = 60°

= <BAC = 60°

∴ <BCA = 30° and <BAC = 60°

Answer 2

Step-by-step explanation:

Listen who ever is asking this question

Just learn 2 types of right angle triangle

30°,60°,90° and 45°,45°,90°

In first one

The ratio of sides = 1 ,√3 ,2 means side in front of angle 30°=1

Angle 60°=√3

Angle 90°=2

And in second one it will be a right isosceles triangle

So the ratio will be

45°=1

45°=1

90°=√2

Why did i say to learn ???

Because many of the questions are based on these angles

And if u know the sides thn u can tell the angles in no timeor u know the angles thn u can tell the sides in no time as well

This is the base of rightangle triangle

Plz learn it if u can