In a triangle ABC right angled at B, AB = 6 cm, BC = 8 cm, The length of hypotenuse AC is
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By using Pythagoras theorem
Hypotenuse ²=perpendicular ²+base²
In∆ABC
AC²=AB²+BC²
AC²=6²+8²
AC²=36+64
AC²=100
AC=√100
AC=10cm
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