Question

in a triangle ABC right angled at Bran A=24/7, find the sin c, cos c,sec c​

Answer 1

In Δ ABC, right-angled at B

Using Pythagoras theorem

AC² = AB² +BC²  

AC² = 576 + 49 = 625

AC = √635

AC = ±25

Now

(i) In a right angle triangle ABC where B=90° ,

Sin A =  

=  

CosA =  

=  

(ii) Sin C =  

=  

Cos C =  

=

Answer 2

Answer:

sinC=7/25 ,cosC=24/25, secC=25/24

Step-by-step explanation:

In∆ABC Rt angled at B

such that, AB=7, BC=24, AC=?

from angle A perpendicular and base are AB & BC

so,tanA=BC/AB=Perpendicular/Base=24/7

BC=Perpendicular=24, AB=Base=7

by using Pythagoras theorem

H²=P²+B²

H=√24²+7²

H=√625

H=25

i.e, AC=25

from angle C the perpendicular and base are AB & BC

So, SinC= 7/25

CosC=24/25

SecC=25/24