Math, asked by yashbhardwaj656, 8 months ago

In a triangle ABC, tanA+tanB+tanC = tanA tanB tanC and tan a/2+tan b/2+tan b/2+tan c/2+ tan c/2+tan a/2=1
If X, Y, Z€R and x+y+z=xyz then x/1+x^2 +y/1+y^2+z/1+z^2 =

Answers

Answered by kknagarathna5
0

Answer:

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