In a triangle ABC,The bidector of triangle A meets BC is perpendicular to BC ,prove that AB=AC
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Let AD is the bisector of angle A to BC then angle DAB=angleDAC
To Prove= AB= AC
Proof= in triangle ADB and triangle ADC
angle DAB = angle DAC(ad is the bisector of angleA)
AD=AD(common)
angle ADB=angle ADC=90degree
Triangle ADB congruent to triangleADC (by A.S.A)
AB=AC(cpct)
Hence proved
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