Question

prove the following:
${e}^{i\pi} - 1 = 0$
with proper reasoning and steps.

thanks for answering ☺️☺️.

Answer 1

substituting x is equal to Pi
e^i*pi=cospi+isinpi
e^i*pi=1+0
e^i*pi-1=0

Answer 2

Step-by-step explanation:

$\begin{lgathered} \sf \: {e}^{i\pi} = \cos(\pi) + i\sin(\pi) (Euler formula)\\ \\ \sf \: = ( - 1) + i(0) \\ \\ \sf \: = - 1$