Question

in a triangle ABC, the bisector of angle B meet AC at D, A line PQ ll AC meet AB,BC and BD at P, Q and R respectively. show that PR x BQ = QR x BP.

Answer 1

Thank you for asking this question. Here is your answer:

BP/BQ  = PR/PQ -- (equation 1)

AB/BC = AD/DC -- (equation 2)

PQ||AC So ΔBPQ ≈ ΔBAC

BP/BA = BQ/BC

BP/BQ = AB/BC --- (equation 3)

so from the equation 1 and equation 2 we can get this:

PR/RQ = AD/DC

Answer 2

Answer:

first show us the diagram