In a triangle ABC, the internal angle bisectors of angle B and angle C meet at O. Prove OA is the bisector of angle A
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let ABC is a isocseles traingle
so B=C
SO B/2 =C/2
in AOB AND AOC
A¹/2+B/2 = A²/2 +C/2
SO A¹/2= A²/2
so B=C
SO B/2 =C/2
in AOB AND AOC
A¹/2+B/2 = A²/2 +C/2
SO A¹/2= A²/2
tusharjindal20p9t6sr:
But if the triangle is not isosceles. Then
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