Question

in a triangle ABC the sum of three interior angle of a triangle is 180°. angle B=70°,angle C=70°,find angle A​

Answer 1

Answer:

40°

Step-by-step explanation:

angle a + angle b + angle c = 180°

angle a + 70 + 70 = 180

angle a = 180-140

angle a = 40°

Answer 2

Given:-

• ∠B of ∆ABC = 70°
• ∠C of ∆ABC = 70°

To find :-

• ∠A of ∆ABC

$\sf\blue{SolutioN}$

Let the ∠A be 'x'.

The sum of all interior angles of triangle is 180° -[Given]

So, According to question:-

$\sf⇒x + 70° + 70° = 180 \\ \sf ⇒x + 140° = 180° \\ \sf⇒x = 180° - 140° \\ \sf⇒x = 40°$

x = ∠A = 40 °

Thus, the ∠A is 40°.

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More information:-

• Triangle is a closed figure.
• It consists of three sides and three angles.
• Perimeter of triangle = A + B + C. In which A , B and C are sides of triangle.
• Area of triangle = ¹/₂ × b × h. In which B is base of triangle and h is height of triangle.