Math, asked by dharmapparekha, 8 months ago

in a triangle ABC the sum of three interior angle of a triangle is 180°. angle B=70°,angle C=70°,find angle A​

Answers

Answered by UDAYW
0

Answer:

40°

Step-by-step explanation:

angle a + angle b + angle c = 180°

angle a + 70 + 70 = 180

angle a = 180-140

angle a = 40°

Answered by MoodyCloud
3

Given:-

  • ∠B of ∆ABC = 70°
  • ∠C of ∆ABC = 70°

To find :-

  • ∠A of ∆ABC

\sf\blue{SolutioN}

Let the ∠A be 'x'.

The sum of all interior angles of triangle is 180° -[Given]

So, According to question:-

 \sf⇒x + 70° + 70° = 180 \\  \sf ⇒x + 140° = 180° \\  \sf⇒x = 180° - 140°  \\  \sf⇒x = 40°

x = ∠A = 40 °

Thus, the ∠A is 40°.

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More information:-

  • Triangle is a closed figure.
  • It consists of three sides and three angles.
  • Perimeter of triangle = A + B + C. In which A , B and C are sides of triangle.
  • Area of triangle = ¹/₂ × b × h. In which B is base of triangle and h is height of triangle.

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