Math, asked by satyamy3550, 10 months ago

In a triangle ABC with fixed base BC, the vertex A moves such that cosB + cosC = 4sin^2\frac{A}{2}. If a, b and c denote the lengths of the sides of the triangle opposite to the angles A, B and C, respectively, then
(a) b + c = 4a
(b) b + c = 2a
(c) locus of point A is an ellipse
(d) locus of point A is a pair of straight lines

Answers

Answered by ruma80
0

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