In a triangle AC=AD=BC,angle DAE=75 degree,find angle y
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AC=AD=BC
DAE=75°
BAD°+DAE°=180°
BAD°+75°=180°
BAD°=180°-75°
BAD°=105°
Let angle Y is Y
y°+y°+105°=180°
2y°+105°=180°
2y°=180°-105°
2y°=75°
y°=37.5°
I hope it right answer
DAE=75°
BAD°+DAE°=180°
BAD°+75°=180°
BAD°=180°-75°
BAD°=105°
Let angle Y is Y
y°+y°+105°=180°
2y°+105°=180°
2y°=180°-105°
2y°=75°
y°=37.5°
I hope it right answer
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Answer:
50 degree is the answer of this question
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