Question

in a triangle, AD is bisector of angleA, meeting side BD at D . AB=10 cm AC=14 cm BC=6cm ,find BD and DC​

Answer 1

Answer:

If AB = 10 cm, AC = 14 cm and BC – 6 cm, find BD and DC. By angle-bisector theorem BD/DC = AB/AC = 10/14 Let BD = x cm and DC = (6-x) (As BC = 6 cm given) x/(6-x) = 10/14 14x = 10(6 – x) 14x = 60 – 10x 14x + 10x

= 60 or x

= 2.5 Or BD

= 2.5

Then DC = 6 – 2.5 = 3.5 cm

Answer 2

Step-by-step explanation:

Given :

• in a triangle, AD is bisector of angleA, meeting side BD at D .

• AB = 10 cm

• AC = 14 cm

• BC = 6cm

To Find :

• find BD and DC

Solution :

Let BD is x Then DC is 6 - x

• According to the ABC

BD / DC = AB / BC

• Substitute all Values :

➭ x / 6 - x = 10 / 14

➭ 14x = 60 - 10x

➭ 14x + 10x = 60

➭ 24x = 60

➭ x = 60 / 24

➭ x = 2.5 Cm

Hence,

• BD = x = 2.5 cm

• DC = 6 - x = 6 - 2.5 = 3.5 Cm