In a triangle angle B=90°.find the sides of the triangle ,if AB=(x-3)cm,BC=(x+4)cm and AC=(x+6) cm
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ac is hypotenuse as angle B is 90
AB^2+ BC^2=AC^2
(x-3)^2 + (x+4)^2 = (x+6)^2
solve this equation to find x and then the sides
AB^2+ BC^2=AC^2
(x-3)^2 + (x+4)^2 = (x+6)^2
solve this equation to find x and then the sides
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