In a triangle angle c=3 angle b =2 (angle a+angel b). find three angle . but this question is linear equation two variable cbse 1991 ask questions Delhi board
Answers
Answered by
2
hey mate
hope it is helpful
hope it is helpful
Attachments:
suraj533:
aap ne right answer give
Answered by
1
Answer :-
Provided
angle c = 3 × angle b
also = 2(angle a + angle b )
Now as we know that sum of all angles in a triangle = 180°
then
angle a + angle b + angle c = 180°
and as c = 2(angle a + angle b )
=> angle a + angle b + 2 angle a + 2 angle b = 180°
=> 3 ( angle a + angle b ) = 180°
or angle a + angle b = 60° ...... (i)
Now it is also provided that angle c = 3 × angle b = 2 angle a + 2 angle b
or 2 angle a = angle b ...... (ii)
from (i)
3 angle a = 60°
or angle a = 20°
therefore from (ii)
angle b = 40°
hence angle c = 3 angle b = 3 × 40
= 120°
So , all angles are
angle a = 20°
angle b = 40°
angle c = 120°
Hope it helps
Provided
angle c = 3 × angle b
also = 2(angle a + angle b )
Now as we know that sum of all angles in a triangle = 180°
then
angle a + angle b + angle c = 180°
and as c = 2(angle a + angle b )
=> angle a + angle b + 2 angle a + 2 angle b = 180°
=> 3 ( angle a + angle b ) = 180°
or angle a + angle b = 60° ...... (i)
Now it is also provided that angle c = 3 × angle b = 2 angle a + 2 angle b
or 2 angle a = angle b ...... (ii)
from (i)
3 angle a = 60°
or angle a = 20°
therefore from (ii)
angle b = 40°
hence angle c = 3 angle b = 3 × 40
= 120°
So , all angles are
angle a = 20°
angle b = 40°
angle c = 120°
Hope it helps
Similar questions