in a triangle omp right angle om=5cm mp=12cm find all trignonmeyric ratios of angle mop
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in the triangle omp
om=5cm
mp=12cm
op==13cm
sin=om/op=5/13
cos=mp/op=12/13
tan=om/mp=5/12
cot=mp/om=12/5
sec=op/mp=13/12
cosec=op/om13/5
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om=5cm
mp=12cm
op==13cm
sin=om/op=5/13
cos=mp/op=12/13
tan=om/mp=5/12
cot=mp/om=12/5
sec=op/mp=13/12
cosec=op/om13/5
I think this will help you
please mark me as a breanlist
minimilisha:
ho
Answered by
3
In right angled triangle OMP,
angle OMP=90°
By pythagoras theorem,
OM^2 +MP^2 = OP^2
5^2+12^2=OP^2
OP^2=25+144=169
OP=13
for angle OMP,
sin O=MP/OP=12/13
cos O=MO/OP=5/13
tan O=MP/OM=12/5
angle OMP=90°
By pythagoras theorem,
OM^2 +MP^2 = OP^2
5^2+12^2=OP^2
OP^2=25+144=169
OP=13
for angle OMP,
sin O=MP/OP=12/13
cos O=MO/OP=5/13
tan O=MP/OM=12/5
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