Question

in a triangle one of the angle is 50% more than the sum of the other two angles .difference of the other two angles is 8 degree find the angles of a triangle

Answer 1

Ans:- x=40, y= 32 ,z=108

Solu :- let x,y,z are the 3 angles of the triangle.

x+y+z =180° ......(1)

let z be the anle which is 50% more than sum of other 2 angles

z =( (x+y)/2)+(x+y) ......(2)

substitute 2 in 1 we get

x+y+x+y+((x+y)/2)=180°
2x+2y+((x+y)/2) =180°
5x+5y=360°

x+y= 72° ......(3)

according to question

x-y=8 .....(4)

from equating 3 and 4 we get

2x =80
x=40
y= 32
z=108