Question

in a triangle,
perimeter=32cm
one side=11 cm
difference of other two sides=5 cm
area=?

Answer 1

let the sides be y and z. x=11cm given.
y+z=21(11+y+z=32)
ATQ
y-z=5( considering y>z)
solving the equation we will get
y=13 and z=8
I think now u can calculate the area

Answer 2

Hey
Here is your answer
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one side=11cm
let 2nd side be Xcm
then third side will be X-5cm
now perimeter=sum of sides
therefore,
11+X+X-5=32
2X+6=32
2X=26
X=13
other side=8cm