Question

in a triangle ,
PQ =2p²-p+1
PR=11p²-3p+5
perimeter =7p²-8p+q
find QR .​

Answer 1

Step-by-step explanation:

$given \: it \: \: PQ = 2 {p}^{2} - p + 1 \\ PR = 11 {p}^{2} - 3p + 5 \\ \\ perimeter \: of \: triangle \: = sum \: of \: sides \\ 7 {p}^{2} - 8p + q = 2 {p}^{2} - p + 1 + 11 {p}^{2} - 3p + 5 + QR \\ - 6 {p}^{2} - 4p + q - 6 = QR \\ \\ hope \: it \: will \: help \: you \:$