Question

In a triangle PQR ,S and T are mid-points of PR and PQ respectively.if the area of triangle PQR is 48cm2(square) then find the area of TSQ .

Answer 1

If we treat PR as the base of PQR, for the purpose of calculating its area,
then since S is the midpoint of PR,
triangle PQS would have half the base of PQR and the same altitude,
so it would have half the area of PQR (that is, 48/2 = 24 square cm).

Now consider PQ as a base of triangle PQS for the purpose of calculating its area.
Since T is the midpoint of PQ,
triangle TSQ would have half the base of PQS and the same altitude,
and so it would have half the area of PQS (that is, 24/2 = 12 square cm).

Answer 2

Answer:

12$cm^{2}$

Step-by-step explanation:

If area of △PQR=48 $cm^{2}$  

If we consider △QSP, then area of this triangle is 24$cm^{2}$ because QS is the median, median divide triangle in equal areas.So, area of △QSP=24$c.m^{2}$

Now in △QSP again 'ST' is median

So, area of △QST=  half of △QSP=   ar(△QSP)

∴ ar△QST=12$cm^{2}$