Question

In a triangle the height is double the base and the area is 400cm2. Find the length of the base and height. I want the answer of this question

Answer 1

The height us double the base.
Therefore h = 2b
Now area = $\frac{1}{2} b h$
400 $cm^{2}$  =  $\frac{1}{2}$(b) (2b)
[2 gets cancelled from the numerator and denominator]
400 cm^2 = b^2
b = $\sqrt{400 cm^{2} }$
b = 20 cm
h = 2b = 2 (20cm) = 40cm