Question

In a triangle, the length of the altitude is double of its base and the area is
400 cm2. Find the length of its base and altitude.

Answer 1

Answer:

base =  20

altitude = 40

Step-by-step explanation:

let base be x

altitude = 2x (given)

area = 400 cm^2

area of triangle = 1/2 base × altitude

400 = 1/2 x×2x

400×2 = 2x^2

2x^2 = 800

x^2 = 800/2

x^2 = 400

x= √400

x = 20

∴ base = x = 20 cm

 altitude = 2x = 2 × 20 = 40 cm