In a triangle the length of the two larger sides are 15cm
and 13 cm the angles of triangle are in an A.P. the
length of the remaining side can be
Answers
Given :----
- Two larger sides of triangle are 15cm and 13cm.
- angles are in AP.
- We have to Find third side ?
Explaination :-----
First of all this is not a right angle triangle and question is absolutely correct . Excellent Question . We can solve it by Sine rule or cosine rule to Find rest two angles, we cant just assume its a right angled triangle for our comfort .
Solution :-----
Let us suppose that , angles of ∆ are (a-d), a and (a+d) since these are in AP .
Now, we know that , sum of all angles of ∆ are 180°.
so,
→ (a-d) + a + (a+d) = 180°
→ 3a = 180°
→ a = 60° .
Now, since , C > B > A , c > b > a
so, c = 15cm , and b = 13 cm
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Now, Lets solve it by sine rule , to Find Exact value of angles , [ we cant take d = 30°] .
Sine rule says that ,
→ [ a/sinA = b/sinB = c/sinC ]
Putting values we get,
→ a/sin(60-d) = 13/sin60 = 15/sin(60+d)
Now, comparing , we get,
→ sin(60+d) = 15*sin60/13 = 15*√3/2/13 [ as sin60° = √3/2]
→ (60+d) = sin^(-1)(0.9926008)
→ (60+d) = 83.025°
→ d = 83.025° - 60° = 23.025°
Putting now,
A = 60° - 23.025° = 36.975°
so,
→ a/sin36.975° = 13/sin60° = 15/sin83.025°
Comparing any now we get,
→ a = 13*sin36.975°/sin60° = 9.02 cm .
Again comparing now,
→ a = 15*sin36.975°/sin83.025° = 9.08cm .....
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So, we can say that, Approx values of third smaller side can be either 9.02 cm or 9.08cm ....
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we can solve this by Cosine rule also ,,
After finding angle B = 60°
→ cos60° = 15²+x²-13²/2*15*x
1/2 = 225 + x² - 169/30x
→ 15x = 56-x²
→ x² - 15x + 56 = 0
→ x² - 7x - 8x + 56 = 0
→ x(x-7) -8(x-7) = 0
→ (x-7) (x-8) = 0
if x - 7 = 0
x = 7cm ,
and if x - 8 = 0 ,
→ x = 8 cm
so, sides can be 7cm and 8cm also....
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Question was easy, only calculation part was tough, as in sine rule we have to use sine inverse .
i hope you understand both methods now, try yourself once ... i told you both methods .. Maths is all about practice yourself , just take hint and than try yourself .
Best of luck .
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