In a triangle the sum of any two sides exceeds the third side by 6cm.its semi-perimeter (in cm)is
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b8ramsakiknishuadwa
30.01.2017
Math
Secondary School
+8 pts
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In a triangle the sum of any two sides exceeds the third side by 6cm then find the area.
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abhi178
Abhi178 ★ Brainly Teacher ★
let a, b, and c are sides of triangle
a/c question
a+b-c=6
b+c-a=6
c+a-b=6
add all equations
a+b+c=18
hence perimeter (s)=18
s-(a+b-c)=18-6
a+b+c-a-b+c=12
2c=12
c=6cm
in the same way
b=a=6cm
hence triangle is an equilatral
so ,
area of equilatral triangle=root3/4 (6)^2
=9root3 cm^2
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Answer:
its pretty simple
Step-by-step explanation:
first, you need to know the area formula of equilateral triangle=root3/4a^2
let triangle be an equilateral triangle
let all equal sides be="a"
it is given that sum of two sides exceeds other by 6
so the equation will be(a+a=a+6)
=2a-a=6
=a=6
now area = root3/4a^2
root3/4*(6)^2
=root3/4*36
=9root3 cm^2