Question

In a triangleABC, if 3angleA = 4angleB = 6angleC then A:B:C= ?
Find answer in ratio?​

Answer 1

Given:

In ∆ABC , 3∠A= 4∠B= 6∠C

Let x= 3∠A= 4∠B= 6∠C

X=3∠A

∠A= x/3

X=4∠B

∠B= x/4

X=6∠C

∠C= x/6

By angle sum property

∠A+∠B+∠C= 180°

Put the value of ∠A, ∠B, ∠C

X/3+x/4+x/6= 180°

L.c.m of 3,4,6 = 12

(4x + 3x +2x) /12 = 180°

9x = 12 × 180

X= (12× 180) /9

X= 240°

∠A= x/3

∠A= 240/3 = 80°

∠B= x/4

∠B= 240/4= 60°

∠C= x/6

∠C= 240/6 = 40°

_____________________________

Hence the angles be

∠A=80°

∠B=60°

∠C= 40°

ratio = 80 : 60 : 40

        = 4 :3 :2

Hope this will help you.....

Answer 2

Answer:

HOPE IT HELPS YOU .!!!!!!.

Step-by-step explanation:

Given parameters

In ΔABC,

3∠A = 4∠B= 6∠C

Let us consider x = 3∠A = 4∠B = 6∠C

x = 3∠A

∠A = x/3………………….(1)

x = 4∠B

∠B = x/4…………………..(2)

x = 6∠C

∠C = x/6…………………….(3)

By using angle sum property

∠A + ∠B + ∠C = 1800

Put the values of ∠A, ∠B, ∠C

x/3 + x/4 + x/6 = 1800

Let us find the L.C.M of 3,4,6 i.e 12

(4x + 3x + 2x)/12 = 1800

9x = 2160

x = 2400

Substitute the value of x in eqaution (1), (2) and (3)

∠A= x/3

∠A= 240/3 = 80°

∠B= x/4

∠B= 240/4= 60°

∠C= x/6

∠C= 240/6 = 40°