In a triangleABC, vertex A is (6,8) and the midpoint of BC is (3,2). then the coordinates
centroid G of AABC is
1) (1,1)
2) (2,1)
3) (3, 4)
4) (4, 4)
In the diagram the coordinates of P, Q and R are (3,6), (-1,3) and (2, -1) respectively, the
ASQR is
1) 12 sq. units
2) 12.5 sq. units
3) 13 sq. units
4) 14 sq. units
P(4,-5) and Q(5,8) are the endpoints of a line segment PQ. The ratio in which PQ is di
the Y - axis is
1)3 : 2 internally 214.5 evtornell..
The di
the res
11
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Coordinates of centroid = (4 , 4) if In a triangleABC, vertex A is (6,8) and the midpoint of BC is (3,2)
Step-by-step explanation:
In a triangle ABC, vertex A is (6,8) and the midpoint of BC is (3,2)
Let say D = midpoint of BC is (3,2)
=> AD is median
Centriod divides Median in 2:1 ratio
=> AB (6, 8) & (3,2) is divided by centroid in 2: 1 Ratio
Coordinates of centroid = (2 * 3 + 1 * 6)/(2 + 1) , (2 *3 + 1 * 6)/(2 + 1)
= 12/3 , 12/3
= 4 , 4
Coordinates of centroid = (4 , 4)
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