Question

in a tringal ABC 'ANGLE A - angle b =15 OR ANGLE B-ANGLE C =30

Answer 1

angle A - angle B=15°,

then

angle A=15°+angle B,

also

angle B - angle C=30°,

then

angle C = angle B - 30°,

hence

angle A + angle B + angle C =180°,

then

(15°+ angle B) + angle B + (angle B - 30°)=180°,

3× angle B - 15° =180°,

3 × angle B =180°+15°,

3×angle B=195°,

then

angle B=195°/3 = 65°,

hence
angle A=15°+65°=80°,

angle C=65°-30°=35°

Answer 2

given a triangle abc

<a-<b=15   or  <a=15+<b ----1      

<b-<c=30  or       <c=<b-30-----2

we know that sum of interior angles of tringles are 180

<a+<b+<c=180------3

put above values in =en 3--,we get

15+<b+<b+<b-30=180

3<b-15=180

3<b=180+15

<b=195/3

<b=65 deg          

now <a=15+<b        <a= 15+65    <a=80deg

<c=<b-30    <c=65-30  <c=35deg

check a+b+c=180

80+65+35=180

180=180

thnx dude may be its usefull