Question

In a trubulent flow through pipe the centre line velocity is 3.61m/s and the friction factor is 0.02.The mean velocity if the flow is in m/s?

Answer 1

Answer:

3.00 m/s

Explanation:

Given:

the centreline velocity, Um = 3.61 m/s

friction factor, f = 0.02

the relation between centreline velocity Um and mean velocity V is given by :

Um/V = 1.43 √f + 1

3.61/V = 1.43 × √0.02 + 1

3.61/V = 1.20

V = 3.61/1.20

V = 3.00 m/s

Answer 2

Thus, the mean velocity of the pipe is V = 3.00m/s.

Given:

Centre line velocity$(u_m)$ = 3.61m/s

Friction factor $(f)$ = 0.02

To Find:

Mean velocity.

Solution:

Here, the relation between the centreline velocity $(u_m)$ and the mean velocity $V$  is given by:

$\frac{u_m}{V} =1.43\sqrt{f+1}$

now, place the given values in the above formula

Here, we get,

$\frac{3.61}{V} =1.43\times \sqrt{0.02+1}$

now, by adding the numbers which are written in square root

we will get,

$\frac{3.61}{V}=1.20$

now, after moving the value of centreline velocity

we get,

$V=\frac{3.61}{1.20} \\V=3.00m/s.$

Thus, the mean velocity of the pipe is V = 3.00m/s.