Question

‘In a tug-of-war , when the two teams are pulling the rope, a stage comes when the rope does not move to either side at all’. Which of the following is the correct reason for this?
(A) Both teams have the same number of members.
(B) There is a lot of competition going on between the two teams.
(C) The net force of forces acting in opposite directions is equal to the difference between the two forces.
(D) The net force of forces acting in opposite directions is equal to the sum of the two forces​

Answer 1

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Explanation: the correct answer is option. C friend.

Hope it’s useful friend…

Good luck and have a great day buddy…

Keep rocking !!

Answer 2

Answer:

The correct answer is option (C) The net force of forces acting in opposite directions is equal to the difference between the two forces.

Explanation:

Tug-of-war: It is a game in which two teams pull a rope towards themselves to reach a flag that is tied at the center of the rope.

As both the teams apply force to pull the rope towards themselves, the forces are acting in the opposite directions.

Let the force applied by team 1 be $F_1$ and by team 2 be $F_2$.

The net force acting on the rope is given by,

$F = F_1-F_2$           --------------- (i)    

[negative sign signifies that both the forces are directed in opposite directions]      

Now the case is that the rope doesn't move to either side at all which means the net force acting on the rope is 0 i.e.,

$F = 0\\F_1-F_2 = 0\\F_1 = F_2$

It means both the teams are applying the same amount of force on the rope.

From equation (i), it is clear that the net force is equal to the difference of the two forces.

Hence, option (C) is correct.

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