Question

In a two digit number digit at the ten's place is twise the digit at unit's place .If the number obtained by interchanging the digits is added to the orignal number, the sum is 66. Find the number​

Answer 1

Answer:

42

Step-by-step explanation:

let number at unit place is X and let at tens place is Y

then according to question Y=2x

now number is 10(2x)+X

after interchanging the digit number obtained as

10x+2x

adding them we get

21x+12x=66

33x=66

X=2

then at tens place Y=2*2=4

so number will be 42