In a two digit number the difference of digits is 4 and 10 times the number is equal to 14 times the sum of the digits of the number and the number formed by reversing the digits. Find the number
A.84
B.26
C.62
D.51
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let units place digit be x-4
ten's place digit = x
number = 10x + x-4 = 11x - 4
number after reversing digits = 10(x-4) + x= 11x - 40
Given
10(11x-4) = 14( 2x - 4 + 11x - 40)
110x - 40 = 14(13x - 44)
110x - 40 = 182x - 616
72x = 576
x= 8
Number = 84
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