In a two digit number, the digit at tens place is four times the digit at unit place. The number obtained by interchanging the digits is 54 less than the original number. Find the original number
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Let the digit at unit's place be x.
Then, ten's digit =4x.
So, number =10*4x +x
=40x+x
=41x
New number =10*x+4x
=14x
Now,
41x-14x=54(given)
→ 27x=54
→ x=2
So, original number =10*4*2+2
=80+2=82.
Then, ten's digit =4x.
So, number =10*4x +x
=40x+x
=41x
New number =10*x+4x
=14x
Now,
41x-14x=54(given)
→ 27x=54
→ x=2
So, original number =10*4*2+2
=80+2=82.
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