Question

In a two- digit number, the digit at the unit place is double the digits in the tens place . the number exceeds the sum of its digits by 18. find the number​

Answer 1

Let the digit at one's place be y and at tens place be x.

According to the question:

☛ 2x = y

➜ 2x - y = 0 ...(1)

☛ 10x + y = x + y + 18

➜ 10x - x + y - y = 18

➜ 9x = 18

➜ x = 2

Putting value of x in (1)

☛ 2x - y = 0

➜ 2(2) - y = 0

➜ y = 4

➜ y = 4

Number = 10x + y

Number = 10(2) + 4

Number = 24

Hence, The required number is 24