in a two digit number the digit at the units place is double the digit in the tens place the number exceeds the sum of its digit by 18 find the number
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Let unit place digit = x
tens digit place=2x
2x+x=18
3x=18
then x=18/3=6
tens digit place=2x
2x+x=18
3x=18
then x=18/3=6
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