Question

In a two-digit number ,the digit at the units place is double the digit in the tens place.The number exceeds the sum of its digits by 18. Find the number.

Answer 1

Hey

Here is your answer,

let the ten's place be x
the units place digit is double the unit place
so unit place=2x
so the number form is x.10+2x.1
                                    10x+2x=12x
the no exceeds the sum of the digit by 18
                                          12x-2x+x=18
                                            12x-3x=18
                                                9x=18
                                              x=18/9
                                             x=2
hence the no is 24= 2x10+4x1

Hope it helps you!