Question

in a two digit number, the digit at the units place is double the digit in the tens place. the number exceeds the sum of its digit by 18. find the number. PLEASE ANSWER FAST

Answer 1

Answer:

Let the digit in the tens place of the number be x. The digit in the units place of the number = 2x∴ The number = 10x + 2x = 12xSum of the digits = x + 2x = 3xGiven that the number exceeds the sum of its digit by 18.

Step-by-step explanation:

it's all me

Answer 2

Answer:

24

Step-by-step explanation:

Let the digit in the tens place of the number be x.

The digit in the units place of the number = 2x

∴ The number = 10x + 2x = 12x

Sum of the digits = x + 2x = 3x

Given that the number exceeds the sum of its digit by 18.⇒ 12x = 3x + 18⇒  9x = 18⇒ x = 2

Therefore the digit in the tens place is 2 and the digit in the units place is 2 x 2 i.e. 4.

So the number is 24.