In a two-digit number, the digit in the tens place is four times the digit in the units place. If
the sum of the digits is 10, find the number.
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Step-by-step explanation:
let tens place digit be x. and unit place be y
x=4y
x-4y=0........ 1
x+y=10.........2
subtract 2 from 1
thus y =2
putting y=2 in 2
x+2=10
x=10-2
x=8
the no is 10x+y=10*8+2
=80+2
=82
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