Question

in a two digit number the digit in the unit place is four times the digit in the tens place and the sum of the digits is equal to ten. what is the number?

Answer 1

Let the digit in unit's place be x
Then digit at tens place will be 4x

Hence the no. formed will be :::::

10 × 4x + x. -------------- (i)

It is given that x + 4x = 10
=> 5x = 10
=> x = 2

Substituting x in eq (i)

10 × 4×2 + 2
=> 80 + 2
=> 82

Hence 82 is the no.

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Answer 2

Digit at units place = x
Digit at tens place = y

According to question,
x = 4y
x + y = 10
5y = 10
y = 2

Then x = 4*2 = 8

Number is 82