taking out the slope of displacement vs time squared graph of a freely falling body,it comes 5 m/s².
because meter when divided by (second)² gives m/ s² which is unit of acceleration.
and in the case of free fall g = 10 m/ s²
then why the slope is not equal to g?
explain
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SLOPE OF GRAPH =
Change in Variable plotted on y-axis / Change in variable plotted on x-axis
If you will take out slope of graph of Velocity vs Time Graph
you will get
=> final velocity - initial velocity / time. i.e. equal to Acceleration.
But if you will take out slope of graph of Displacement vs Time Graph
then you will get
=> Displacement / Time
=> Velocity
So on finding slope of graph of Displacement vs Time Graph you will get VELOCITY NOT ACCELERATION.
Change in Variable plotted on y-axis / Change in variable plotted on x-axis
If you will take out slope of graph of Velocity vs Time Graph
you will get
=> final velocity - initial velocity / time. i.e. equal to Acceleration.
But if you will take out slope of graph of Displacement vs Time Graph
then you will get
=> Displacement / Time
=> Velocity
So on finding slope of graph of Displacement vs Time Graph you will get VELOCITY NOT ACCELERATION.
amal14:
read the question carefully
I said displacement vs time squared graph
not displacement vs time graph
then also it will come out to be velocity square
how
m/s/s = m/s²
the slope will come acceleration not velocity
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