In a two digit number the digit in the unit place is twice of the digit in the tenth place . if the digits are reversed , the.new number is 27 more than the given number . find the number ?
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Let us assume, x and y are the two digits of a two-digit number.
Therefore, the two-digit number = 10x + y and the reversed number = 10y + x
Given:
y = 2x -------------1
Also given:
10y + x = 27 + 10x + y
9y - 9x = 27
y - x = 3
substitute the value of y from equation 1 in equation 2
2x - x = 3
x =3
Therefore, y = 2 * 3 = 6
Therefore, the two digit number = 10x + y = 10 * 3 + 6 = 36
Therefore, the two-digit number = 10x + y and the reversed number = 10y + x
Given:
y = 2x -------------1
Also given:
10y + x = 27 + 10x + y
9y - 9x = 27
y - x = 3
substitute the value of y from equation 1 in equation 2
2x - x = 3
x =3
Therefore, y = 2 * 3 = 6
Therefore, the two digit number = 10x + y = 10 * 3 + 6 = 36
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