Question

In a two-digit number, the digit in the unit place
more than twice the digit
When the digits
digit in the tens places
are reversed, the number obtained
is 45 more than the original
than the original number. Find the
original


number.
​

Answer 1

Step-by-step explanation:

Let the tens place be y

unit place digit = 2y + 1

No. = 10( y) + ( 2y + 1)

10y + 2y + 1

= 12y + 1

reversed no. = 10(2y+1) + y

2y + 10 + y

= 21y + 10

According to the Question

Original no. + 45 = reversed no.

= 12y + 1 + 45 = 21y + 10

= 12y - 21y = 10 - 46

= -9y = -36

= y = -36/ ( -9)

y = 4

=== tens place digit = 4

unit place = 9

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