In a two digit number, the digit in the unit's place is two more than the three times of the digit in ten's place. If the sum of the two digits is 6, the number is ?
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let digit at unit's place is x
& digit at ten's place is y
so x= 3y+2 .... (1)
Also x + y = 6 ....(2)
Substituting value of x from equation (1) in equation (2), we get
3y + 2 +y = 6
4y = 4
y = 1
so x =3y+2 = 3(1)+2 = 5
Answer: x=5 y=1 so the number is 15
Got it? Any Doubt?
& digit at ten's place is y
so x= 3y+2 .... (1)
Also x + y = 6 ....(2)
Substituting value of x from equation (1) in equation (2), we get
3y + 2 +y = 6
4y = 4
y = 1
so x =3y+2 = 3(1)+2 = 5
Answer: x=5 y=1 so the number is 15
Got it? Any Doubt?
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