Math, asked by parthv786p6wx4o, 1 year ago

In a two digit number, the digit in units' place is twice that in the ten's place and if 2 is subtracted from the sum of the digits the result is equal to 1/6 of the number. what is the original number.

Answers

Answered by Bunti360
30
Here is the solution :

Let the two digit number be ab,

Where ab = 10a + b, and b = 2*a,

According to the Question,

a+b - 2 = 1/6(10a+b)

=> Multiplying 6 on both sides,

=> 6a + 6b - 12 = 10a + b

=> 5b = 4a + 12,

Subtracting (b + 6a - 12 ) on both sides,

Substituting b = 2*a,

=> 5(2a) = 4a + 12,

=> 10a = 4a + 12,

=> Subtracting 4a on both sides,

=> 6a = 12,

=> Dividing 6 on both sides,

=> a = 2,

=> b = 2*2 = 4,

Therefore : The number is 24

Hope you understand, Have a Great day :D,
Thanking you, Bunti 360 !.
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