In a two digit number, the digit in units' place is twice that in the ten's place and if 2 is subtracted from the sum of the digits the result is equal to 1/6 of the number. what is the original number.
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Here is the solution :
Let the two digit number be ab,
Where ab = 10a + b, and b = 2*a,
According to the Question,
a+b - 2 = 1/6(10a+b)
=> Multiplying 6 on both sides,
=> 6a + 6b - 12 = 10a + b
=> 5b = 4a + 12,
Subtracting (b + 6a - 12 ) on both sides,
Substituting b = 2*a,
=> 5(2a) = 4a + 12,
=> 10a = 4a + 12,
=> Subtracting 4a on both sides,
=> 6a = 12,
=> Dividing 6 on both sides,
=> a = 2,
=> b = 2*2 = 4,
Therefore : The number is 24
Hope you understand, Have a Great day :D,
Thanking you, Bunti 360 !.
Let the two digit number be ab,
Where ab = 10a + b, and b = 2*a,
According to the Question,
a+b - 2 = 1/6(10a+b)
=> Multiplying 6 on both sides,
=> 6a + 6b - 12 = 10a + b
=> 5b = 4a + 12,
Subtracting (b + 6a - 12 ) on both sides,
Substituting b = 2*a,
=> 5(2a) = 4a + 12,
=> 10a = 4a + 12,
=> Subtracting 4a on both sides,
=> 6a = 12,
=> Dividing 6 on both sides,
=> a = 2,
=> b = 2*2 = 4,
Therefore : The number is 24
Hope you understand, Have a Great day :D,
Thanking you, Bunti 360 !.
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