Question

In a two digit number the sum of the digits is 7 If the number with the order of digits reversed is 28 greater than the twice of the units of the original number find the number?

Answer 1

Given sum of the digits is 7. We get 6 possibilities.

original. reversed
16 61
25 52
34 43
43 34
52 25
61 16

given the reversed number should be 28 greater than the twice of the digit in units place of original number.

That means if we consider 61, it's reversed number(16) should be 28+2(1) (since 1 is the unit's digit of original number)
16=28+2(1). ( But here 16 itself is less than 28.) Therefore 16 can be ignored.
Using the same logic 52( reversed number 25) can also be ignored.

Taking rest of the cases
16-61
28+2(6)=40≠61
25-52
28+2(5)=38≠52
34-43
28+2(4)=36≠43
43-34
28+2(3)=34( The reversed number of the original number).

Therefore the answer is 43.