in a two digit number the sum of the digits is 7 if the number with the order of the digits are reversed is 20 greater than twice the units digit of the original number find the number
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Let the original number be 10(7-x)+x
Here, X is the one's digit and (7-X) is the tens digit which is why we multiply it with 10.
The reversed number would be 10x+(7-x)
We know, 10x+(7-x)=28+2x
=>10x+7-x=28+2x
=>10x-2x-x=28-7
=>7x=21
=>x=3
Hence, the original number is 10(7-3)+3= 43.
Hope it helps!
Here, X is the one's digit and (7-X) is the tens digit which is why we multiply it with 10.
The reversed number would be 10x+(7-x)
We know, 10x+(7-x)=28+2x
=>10x+7-x=28+2x
=>10x-2x-x=28-7
=>7x=21
=>x=3
Hence, the original number is 10(7-3)+3= 43.
Hope it helps!
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