Question

two numbers are in the ratio of 3:5. if each is increased by 10 the ratio formed is 5:7. find their original numbers.

Answer 1

Here is your solution

Given :-

Two numbers are such that the ratio between them is 3:5.

If each is increased by 10, the ratio between the new numbers so formed is 5:7.

find the original numbers.

Let x

3x = one number

5x = the other number

A/q

If each is increased by 10, the ratio between the new numbers so formed is 5:7.

5x+10/3x+10=5/7

Cross multiply

5(5x+10) = 7(3x+10)

25x + 50 = 21x + 70

25x - 21x = 70 - 50

4x = 20

x = 20/4

x = 5

Hence ,

3(5) = 15 is the 1st number

5(5) = 25 is the 2nd number 

Hope it helps you

Answer 2

I hope it will helps