in a two digit number the sum of the two digits is 9.if 45 is subtracted from the number it's digits are reversed .find the number
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2
Answer:
72
Step-by-step explanation:
let the digits be x and y.
so the number becomes 10x+y
ATQ,
X+Y=9-----------(1)
CASE 2 AFTER INTERCHANGING THE DIGITS , THE NUMBER BECOMES 10Y+X
10X + Y - 45 = 10Y+X
10X+Y- 10Y - X = 45
9X - 9Y = 45
TAKING 9 COMMON
9(X - Y) = 45
X - Y= 45/9
X -Y = 5 ------------(2)
ELIMINATING THE TWO EQUATIONS
X+Y = 9
X-Y = 5
----------------
- + -
2Y = 4
Y = 4/2
Y = 2
PUTTING VALUE OF Y IN EQ 1
X+ 2 = 9
X= 9-2= 7
THEREFORE THE NUMBER BECOMES
10 (7)+ 2= 70+2= 72
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