in a two digit number the tens digit is 3 times the units digit when the number is decreased by 54 the digits are reversed find the number
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93 - Ans.
Soln.
Let ones digit be x so tens digit be 3x
=) Number = 10 X 3x + x
= 31x
Given that 31x - 54 = reverse of 31x
= 10 X x + 3x
= 13x
=) 31x-13x=54
=)18x=54
=)x=54/18=3
So original no. = 3X3X10 + 3= 93
Soln.
Let ones digit be x so tens digit be 3x
=) Number = 10 X 3x + x
= 31x
Given that 31x - 54 = reverse of 31x
= 10 X x + 3x
= 13x
=) 31x-13x=54
=)18x=54
=)x=54/18=3
So original no. = 3X3X10 + 3= 93
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