Question

In a two digit number the unit digit is thrice the ten's digit .If 36 is added to the number the digits interchange the places .find the number​

Answer 1

Step-by-step explanation:

We Have :-

A Two Digit Number

To Find :-

The Number

Solution :-

Let the number be xy

y = 3x

10x + y

10x + y + 36 = 10y + x

9x + 36 = 9y

9y - 9x = 36

9 ( y - x ) = 36

y - x = 4

substituting y = 3x

3x - x = 4

2x = 4

x = 2

y = 3x

y = 3 × 2

y = 6

Number is 26

Answer 2

$\large{\underline{\green{\rm{Let:}}}}$

• The ones digit be X
• The ten's digit be Y
• The number be 10Y+X

$\large{\underline{\red{\rm{Given:}}}}$

In 2 digit number the units is thrice the ten's digit

• by solving here

$\bold{\implies X=3y----(2)}$

If 36 is added to number the digits interchange the places

$\bold{\implies 10y+x+36=10x+y}$

$\bold{\implies 10x-x+y-10y=36}$

$\bold{\implies 9x-9y=36}$

$\bold{\implies x-y=4----(2)}$

• putting the value of X=3y in EQ 1

$\bold{\implies 3y-y=4}$$\bold{\implies y=2}$

• putting the value of y=2 in EQ 1

$\bold{\implies x=3*2}$$\bold{\implies x=6}$

Hence,

The number=10y+X=10×2+6=26

$\large{\boxed{\red{\rm{AnswEr:26}}}}$