In a two similar traingles triangle DEF and traingle ABC.If BC =8cm and 2AB=DE ,then find the length of EF
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Answered by
2
Hey,
We know that ABC is similar to DEF
hence,
ab/DE=BC/ef=AC/df
2ab=DE
hence,
2bc=ef
ef=8*2
=16cm.
HOPE IT HELPS:-))
We know that ABC is similar to DEF
hence,
ab/DE=BC/ef=AC/df
2ab=DE
hence,
2bc=ef
ef=8*2
=16cm.
HOPE IT HELPS:-))
Answered by
2
Here is the solution !
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